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What must be added to x³- 3x² - 12x +19 so that te result is exactly divisible by x² + x - 6?

2 Answers

2 votes

Answer:

this is the correct answer

What must be added to x³- 3x² - 12x +19 so that te result is exactly divisible by-example-1
User Edison Trutwein
by
7.7k points
3 votes

Answer:

2x+5

Explanation:

Just divide the given data.

Given: f(x)=x

3

−3x

2

−12x+19

g(x)=x

2

+x−6

By division algorithm

f(x)=g(x)×q(x)+r(x)

q(x)=

g(x)

f(x)+[−r(x)]

If means r(x) must be added so that result is exactly divisible by x

2

+x−6.

So, 2x+5 must be added to f(x), so that the result is exactly divisible by x

2

+x−6.

User Soroush Mirzaei
by
6.9k points