Answer:
Question 1 : V equals 355 over 113 times 4 squared times 6
Question 2: 400π m3
Question 3: 30.55 cubic feet
Question 4: 64 inches
Question 5: 211.38 gallons
Question 6: 70.65 in³
Question 7: 42 over 11 inches
Explanation:
For all four questions, the formula used for the volume of a cylinder is
V = πr²h
where r = radius of the cylinder = diameter / 2
h = height
Question 1
The radius of the cake is diameter/2 = 8/2 = 4 in
The height of the cake = 5 in
Therefore the volume of batter required is
V = π x 4² x 6
With π = 355113 that works out to
V = 355/133 x 4² x 6
This corresponds to the last choice given as:
V equals 355 over 113 times 4 squared times 6
Question 2
Given diameter = 10, r = 10/2 = 5 meters
h = 16 meters
V = π x 5² x 16
V = π x 25 x 16
V = π x 400
V = 400π m³
This corresponds to the first choice
Question 3
The phrase "...segment from one point on the circular base to another point on the base through the center.."
is nothing but a convoluted expression for the diameter!
So diameter = 8.2 feet
radius r = 3.2 / 2 = 1.6 feet
h = 3.8 feet
π = 3.14
V = πr²h
V = 3.14 x (1.6)² x 3.8
= 3.14 x 2.56 x 3.8
= 30.54592
= 3.55 cubic feet rounded to nearest hundredth
This is the fourth (and last) option
Question 4
Volume is given as 4096π in³
r = 16/2 = 8 inches
r² = 8² = 64
Since V = πr²h,
h = V/πr²
= 4096π/64π
= 64 inches
Option 3
Question 5
r = 3/2 = 1.5 feet
h = 4 feet
π = 3.14
V =3.14 x (1.5)² x 4
= 28.26 cubic feet
Since 1 cubic foot = 7.48 gallons,
28.26 cubic feet = 28.26 x 7.48 = 211.3848 = 211.38 gallons (rounded)
This the third option
Question 6
Volume of each coin = 3.14 x 1.2² x 0.0625 = 2.826 cubic inches
For 250 coins, the total volume = 2.826 x 250 = 70.65 in³
Question 7
V = 1 1/3 in³ = 4/3 in³
r = 1/3 in
π =22/7
V = πr²h
h = V/πr²
r² = 1/3 x 1/3 = 1/9
πr² = 22/7 x 1/9 = 22/63
h = V/πr² = 4/3 ÷ 22/63 = 4/3 x 63/22 = 252/66
= 42/11 (by dividing numerator and denominator by 6)
= 42 over 11 (third choice)