Question

A 40.0 mL volume of 1.80 M Fe(NO3), is mixed with 21.5 mL of 0.808M Fe(NO3), solution.

Calculate the molar concentration of the final solution.

Answer 1

concentration = 1.17M

Step-by-step explanation:

When dealing with dilutions, the number of moles of solute does not change. Therefore, concentration times volume (cV) = constant. i.e.
`c_(1)V_(1)=c_(2)V_(2)`. Original concentration times original volume equals final (total) concentration times final volume.

Therefore, substituting values into the formula, first by changing units provided to standard SI units (mL ⇒ L),

`(1.80)(0.04)=c(0.04+0.0215)\\c=1.17 molL^(-1)`