Answer:The amount of energy released can be calculated using the equation for heat transfer:
Q = mcΔT
Where:
Q = heat transfer in joules (J)
m = mass of water in grams (g)
c = specific heat capacity of water = 4.184 J/g°C
ΔT = change in temperature in °C
Substituting the values:
Q = (75.0 g)(4.184 J/g°C)(100.0ºC - 27.5ºC)
Q = (75.0 g)(4.184 J/g°C)(72.5ºC)
Q = 26,580 J
Therefore, 26,580 J of energy is released when 75.0 grams of water is cooled from 100.0ºC to 27.5ºC.
Step-by-step explanation: