Question

Given that f(x) = x - 3, g(x) = 4x and h(x) = 2f(x - 3) + g(x+1),

then what is the value of h(6)?

Answer 1

h(x)= 2f(x-3) + g(x+1)

h(x)= 2(x-3-3)+4x+1

h(x)= 2(x-6)+4x+1

h(x)=2x-12+4x+1

h(x)=6x-11

h(6)=36-11

h= 25

Answer 2

Answer: The value of h(6) is 28.

Step-by-step explanation: First, we need to calculate the value of f(x-3):f(x-3) = (x-3) - 3 = x - 6

Next, we need to substitute this into h(x) and simplify:h(x) = 2f(x-3) + g(x+1) = 2(x-6) + 4(x+1) = 6x - 8

Finally, we can substitute x = 6 to find h(6):h(6) = 6(6) - 8 = 28