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Find the period and the amplitude of the periodic function. I'm awful with graphs :(

User Tspore
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A period is the difference in x over which a sine function returns to its equivalent state and the amplitude is A/5.

Amplitude:

The amplitude of a periodic variable is a measure of its change over a period of time, such as a temporal or spatial period. The amplitude of an aperiodic signal is its magnitude compared to a reference value. There are various definitions (see below) of amplitude, which is any function of the magnitude of the difference between the extreme values ​​of a variable. In the previous text, the phase of a periodic function is called the amplitude.

X = A sin (ω[ t - K]) + b

A is the amplitude (or peak amplitude),

x is the oscillating variable,

ω is angular frequency,

t is time,

K and b are arbitrary constants representing time and displacement respectively.

According to the Question:

An equation does not have an amplitude. This "equation" represents the formula of a vibration, and was better written as:

X= A/5* sin(1000.t + 120)

These oscillations have a certain amplitude. X values ​​can vary from minimum to maximum. Normally, the stop position of the oscillation is X=0. In this case, we can see that the maximum occurs when the sine is +1 and the minimum occurs when the sine is -1.

For theses cases X= A/5 respectively -A/5.

Therefore,

The amplitude is A/5.

For formulas of this type, the term in front of the sinus (or cosine) is equal to the amplitude.

Complete question:

Can I find the amplitude of this equation? A/5 *

Find the period and the amplitude of the periodic function. I'm awful with graphs-example-1
User Juha Vehnia
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