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Bilquis owns a food truck that sells tacos and burritos. She sells each taco for $4 and each burrito for $6.25. Bilquis must sell a minimum of $630 worth of tacos and burritos each day. Write an inequality that could represent the possible values for the number of tacos sold, t, and the number of burritos sold, b, that would satisfy the constraint.

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Answer:You can graph these equations as you would a normal linear equation. For the first equation, you can shade in the area under the line, and for the other 2 shade in the are above the line. Whatever area of the graph all three shaded areas overlap gives us our possible range of answers, with each point in said area read as (x,y), with x the number of tacos sold and y the number of burritos sold.

Explanation:

Let's refer to the number of burritos sold as B and the number of tacos sold as T.

We can go through statements one by one and write an inequality for each, then see if there's any that we can consolidate.

She has enough supplies to make 130 tacos or burritos gives us the equation:

B+T < 130

She sells each taco for $3.75 and each burrito for $6. Ava must sell a minimum of $600 worth of tacos and burritos each day. These statements can be combined to give us the following:

3.75T+6B > 600

She must sell a minimum of 80 burritos gives us:

B > 80

Because the number of burritos sold is going to be our y value, we can rearrange all of these to be in terms of the number of tacos sold. This gives us the following system of equations:

B < 130-T

B > 100-0.625T

B > 80

User Tim Skov Jacobsen
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The inequality representing the possible values for the number of tacos sold (t) and the number of burritos sold (b) that would satisfy the constraint of selling a minimum of $630 worth of tacos and burritos each day is:

4t + 6.25b ≥ 630

This inequality states that the total revenue from tacos (4t) and burritos (6.25b) must be greater than or equal to $630. So, the number of tacos and burritos sold can vary as long as the inequality is satisfied.
User Gajendra
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