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how many moles of sodium are needed to react with sulfric acid to produce 3.75 moles of sodium according to the unbalanced reaction:____ Na + H2(SO4) +___ H2

User EliSherer
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1 Answer

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Answer:n NA = 7.5 mol

Explanation:balanced reaction:

2Na + H2(SO4) → Na2(SO4) + H2

∴ n Na2SO4 = 3.75 mol

⇒ n Na = ( 3.75 mol Na2(SO4) )*(2 mol Na/mol Na2(SO4))

⇒ n Na = 7.5 mol

User Ruslan Batdalov
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