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Calculate the freezing point of an aqueous 0.17 m solution of FeCl3 using a van't Hoff factor of 3.3. (Assume that Kf of water is 1.86∘C/m.)

User Disfigure
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Final answer:

To calculate the freezing point of an aqueous 0.17 m solution of FeCl3, we can use the formula δT = Kf × m × i, where δT is the freezing point depression, Kf is the freezing point depression constant, m is the molality of the solution, and i is the van't Hoff factor. Substituting the given values into this formula, we can calculate that the freezing point of the solution is -1.1002°C.

Step-by-step explanation:

To calculate the freezing point of an aqueous 0.17 m solution of FeCl3, we need to use the formula:

ΔT = Kf × m × i

where ΔT is the freezing point depression, Kf is the freezing point depression constant (1.86°C/m for water), m is the molality of the solution, and i is the van't Hoff factor.

Given that the molality is 0.17 m and the van't Hoff factor is 3.3, we can substitute these values into the formula:

ΔT = 1.86°C/m × 0.17 m × 3.3

ΔT = 1.1002°C

Therefore, the freezing point of the solution is -1.1002°C.

User JuanDYB
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