The reaction equation given is B: 4NH3 + 6NO → 5N2 + 6H2O.
From this equation, we can see that for every 4 moles of NH3 (ammonia), 5 moles of N2 (nitrogen gas) are produced.
To find the number of moles of nitrogen gas produced from the production of 250 grams of water, we need to first find the number of moles of water produced. We can use the molar mass of water, which is 18 grams per mole, to convert the mass of water to moles:
moles of water = 250 grams / 18 grams/mole = 13.89 moles
Next, we can use the stoichiometry of the reaction to determine the number of moles of nitrogen gas produced. According to the reaction equation, for every 6 moles of water produced, 5 moles of nitrogen gas are produced:
moles of nitrogen gas = 5 moles / 6 moles * 13.89 moles = 11.57 moles
So, 11.57 moles of nitrogen gas are produced when 250 grams of water are produced in reaction B.