Question

4)

How many mol of NH, are needed to produce 27
mol of water?
Rxn B: 4NH3 + 6NO → 5N₂ + 6H₂O
Unknown:
Given:

Answer 1

To determine the number of moles of NH3 needed to produce 27 moles of H2O, we need to use the coefficients in the balanced chemical equation for the reaction:

4NH3 + 6NO → 5N2 + 6H2O

Since the coefficients represent the stoichiometric ratios between the reactants and products, we can use them to determine how many moles of NH3 are needed for a certain amount of H2O produced.

For every 6 moles of H2O produced, 4 moles of NH3 are consumed. Therefore, to produce 27 moles of H2O, we need 4 * (27 moles H2O / 6 moles H2O/mol NH3) = 27 moles H2O / (6 moles H2O / 4 moles NH3) = 27 * (4 moles NH3 / 6 moles H2O) = 18 moles of NH3.

So, 18 moles of NH3 are needed to produce 27 moles of H2O.