Question

How many moles are in 56.1 grams of CaCO3

Answer 1

Moles, Molar Mass and Mass

We can use the following equation to depict this relationship:

`n=(m)/(M)`

• n = moles
• m = mass
• M = molar mass

Solving the Question

`n=(m)/(M)`

We're given that the mass is 56.1 g:

`n=(56.1)/(M)`

From a periodic table, we can deduce that the molar mass of CaCO₃ is 100.087 g/mol (taken from ChemSpider):

`n=(56.1)/(100.087)`

`n=0.561`

Answer

0.561 moles