Question

Find the vertex
y=x^2-2x-5

Answer 1

`\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{-2}x\stackrel{\stackrel{c}{\downarrow }}{-5} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ -2}{2(1)}~~~~ ,~~~~ -5-\cfrac{ (-2)^2}{4(1)}\right) \implies \left( - \cfrac{ -2 }{ 2 }~~,~~-5 - \cfrac{ 4 }{ 4 } \right) \\\\\\ \left( 1 ~~~~ ,~~~~ -5 -1 \right)\implies {\Large \begin{array}{llll} (1~~,~-6) \end{array}}`