Answer:
aₙ = 2n+ 3
Explanation:
The general equation for the nth term of an arithmetic series with common difference d and first term a(1) is given by
aₙ = a₁ + d(n - 1)
Using values for the 5th and 15th terms we get
a₅ = a₁ + d(5 -1) = 13
==> a₁ + 4d = 13 (1)
a₁₅ = a₁ + d(15 - 1) = 33
a₁ + 14d = 33 (2)
Eq (2) - Eq(1) gives us:
a₁ + 14d - (a₁ + 4d) = 33 - 13
a₁ + 14d - a₁ - 4d = 20
a₁ - a₁ + 14d - 4d =20
10d = 20
d = 2
Plugging d = 2 in (1) we get:
a₁ + 4(2) = 13
a₁ + 8 = 13
a₁ = 13 - 8 =5
So first term is 5,common difference is 2
Expression for nth term:
aₙ = 5 + 2(n - 1)
aₙ = 5 + 2n - 2
aₙ = 2n+ 3