Final answer:
The molarity of calcium ions in the solution is 0.075 M and the molarity of chloride ions is 0.150 M. Therefore, the molarity of calcium ions is half the molarity of the calcium chloride solution, which is 0.150 M divided by 2, equaling 0.075 M.
Step-by-step explanation:
To calculate the molarity of ions in a solution of calcium chloride, CaCl₂, we need to consider the dissociation of CaCl₂ into its constituent ions.
In water, CaCl₂ dissociates into one calcium ion, Ca²+, and two chloride ions, Cl-.
Therefore, the molarity of calcium ions is half the molarity of the calcium chloride solution, which is 0.150 M divided by 2, equaling 0.075 M.
The molarity of chloride ions is the same as the molarity of the calcium chloride solution, which is 0.150 M.