Question

Solve by elimination. {4x+2y=−6

{3x−2y=13
A. (−2,−5)
B. (1,−5)
C. infinite number of solutions
D. (0,−3)

Answer 1

The answer is B A is no good since negatives are there so as D since it’s 0 while C doesn’t make sense so the reasonable answer is B

Answer 2

[B]. (1,-5)

Explanation:

Given:

`\begin{bmatrix}4x+2y=-6\\ 3x-2y=13\end{bmatrix}`

Solve:

`\begin{bmatrix}4x+2y=-6\\ 3x-2y=13\end{bmatrix}` Since 2y - 2y = 0 we take that away now we have;

`4x=-6\\3x=13` Add 4x + 3x = 7x

`(7x)/(7) =(7)/(7)` Divide both sides by 7.

`x=1`

Now substitute x to find y.

`4(1)+2y=-6`

`4 + 2y =-6` Add 6 to the other side.

`10 = 2y` Divide both sides by 2.

`(10)/(2) =(2y)/(2)`

`y = 5`

Hence, the answer is [B]. (1,-5)

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