Explanation:
the zeros are the x-intercepts. because these are x values, when y (= f(x)) = 0.
a quadratic equation has 2 zeros (even if they are equal or complex numbers).
a quadratic equation
ax² + bx + c = 0
can always be solved by
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
x = (-14 ± sqrt(14² - 4×2×20))/(2×2) =
= (-14 ± sqrt(196 - 160))/4 =
= (-14 ± sqrt(36))/4 = (-14 ± 6)/4
x1 = (-14 + 6)/4 = -8/4 = -2
x2 = (-14 - 6)/4 = -20/4 = -5
these are the 2 zeros (x-intercepts).
if you need the explicit points :
(-5, 0) and (-2, 0)
the y-intercept is the y-value when x = 0
y = 2×0² + 14×0 + 20 = 20
the explicit point : (0, 20)