Answer:
154.61 g.
Step-by-step explanation:
he balanced chemical equation for the reaction of KCIO3 to form KCl and O2 is:
2KCIO3 -> 2KCl + 3O2
From this equation, we can see that for every 1 mole of KCIO3, 2 moles of KCl and 3 moles of O2 are produced.
First, we need to calculate the number of moles of KCIO3:
n = mass / molar mass
= 125g / (138.2 g/mol)
= 0.902 moles
Now that we have the number of moles of KCIO3, we can calculate the masses of the products:
Mass of KCl = 0.902 moles * (74.55 g/mol) = 67.53 g
Mass of O2 = 0.902 moles * (32.00 g/mol) * 3 = 87.08 g
So the total mass of the products will be:
67.53 g + 87.08 g = 154.61 g.
ALLEN