Final answer:
In a series combination of capacitors, the voltage drop across each capacitor is different and depends on their respective capacitances. However, the charge on each capacitor is the same.
Step-by-step explanation:
In a series combination of capacitors, the voltage drop across each capacitor is different and depends on their respective capacitances.
However, the charge on each capacitor is the same. Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage drop, we can find the charges on each capacitor.
Since the voltage drop across C1 is given as 10.0 V, we can calculate the charge on C1 as Q1 = C1 * V1 = (10.0 V)(C1).
Since the capacitors are in series, Q1 = Q2 = Q3. Therefore, Q3 = Q1 = (10.0 V)(C1).