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Using the Lewis Dot Structure, how can we show whether an element with 5 electrons is more likely to either gain 3 or lose 5 electrons in its’ outer-most valence electron shell?

User OrcusZ
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Answer: An element with 5 electrons is more likely to either gain 3 electrons in its’ outer-most valence electron shell

Explanation: To determine whether an element with 5 electrons is more likely to gain 3 or lose 5 electrons in its outermost valence electron shell, we can use the Lewis Dot Structure.

1. Draw the symbol of the element. For example, let's consider the element with 5 electrons as X.

2. Determine the number of valence electrons for the element. Since the element has 5 electrons, it will have 5 valence electrons.

3. Represent the valence electrons as dots around the symbol of the element. In this case, we would draw 5 dots around the symbol X.

4. Analyze the electron configuration to determine the stability of the element.

- If the element gains 3 electrons, it will have a total of 8 valence electrons. This would result in a stable electron configuration, similar to the nearest noble gas. For example, if the element is in Group 15, gaining 3 electrons would give it the electron configuration of the noble gas, Neon (2, 8).

User Lawakush Kurmi
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