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As a warehouse worker pushes a crate across a concrete floor, the force he applies is not perfectly horizontal, as shown in the image below. If the coefficient of kinetic friction between the crate and concrete floor is 0.5, what is the net force on the crate?

A. 87 N
B. 110 N
C. 77 N
D. 135 N

1 Answer

1 vote
The net force on the crate can be calculated using the formula Fnet = μmgcosθ, where μ is the coefficient of kinetic friction, m is the mass of the crate, g is the acceleration due to gravity, and θ is the angle between the force applied and the horizontal. In this case, μ = 0.5, m = 200 kg, g = 9.8 m/s2, and θ = 30°. Therefore, the net force on the crate is Fnet = (0.5)(200)(9.8)(cos30°) = 110 N. Therefore, the correct answer is B. 110 N.
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