Answer: The bushes cost $8 and the shrubs cost 7$
Explanation:
For this question you must use system of equations, trial and error will take a very long time.
So yeah, here is how you solve it-
First set up equations (b represents the amount of bushes and s represents the amount of shrubs):
5b + 1s = 47
10b+4s=108
Next you can either solve via elimination or the substitution method. I will show elimination here. Elimination works by slightly modifying one of the equations so that it cancels when it is added to the other equation:
(I modified the first equation)
-4(5b+1s = 47) = -20b-4s=-188
(Then add)
-20b-4s=-188
+ 10b+4s=108
This equals: -10b=-80
Next you just solve for b:
b=-80/-10
b=8
To then find s, plug b into one of the original equations and solve for s:
(I plugged it into the first equation)
5(8)+1s=47
40+s=47
s=7
So the bushes cost $8 and the shrubs cost 7$
Hope this helps :)