Question

- How much energy was added to 2.26 grams of water to be heated from 25.0° C to 50.0° C?

Answer 1

please use

`H=mC\Delta T`

here m = mass = 2.26 grams\

C = specific heat capacity of water that is 4.2 j / g C

delta T is the difference in temperature.

H = 2.26 * 4.2 * (50 - 25)

H = 237.3 J

so the answer is,

the energy needed is 237.3 Joule or 237.3 J