Question

What is the surface area of the box,in square meters,that Isaiah decorates?

Answer 1

To find the total surface area of the box, we have to find the area of each part.

Area of the two equal triangles.

`A_{\text{triangles}}=2(bh)/(2)=bh`

Where b = 7m and h =8m.

`A_{\text{triangles}}=7m*8m=56m^2`

Now, let's find the area of each rectangle because they are different,

`\begin{gathered} A_1=bh=13m\cdot7m=119m^2 \\ A_2=bh=13m\cdot8m=104m^2 \\ A_3=bh=13m\cdot10.63m=138.19m^2 \end{gathered}`

Then, we add all the areas

`A_{\text{total}}=56+119+104+138.19=417.19m^2`

Hence, the total surface area is 417.19 square meters.