Question

The point A(2, 1) is a vertex of a square ABCD. M(5, 1) is the point of intersection of the

diagonals of the square. Find the coordinates of B, C and D. (Remember: The diagonals
of a square are equal in length and bisect each other at right angles.)

pls give serious answers!!

Answer 1

Explanation:

Since M is the point of intersection of the diagonals of the square, it is also the midpoint of both diagonals. This means that AM is equal to half the length of a side of the square and also bisects the angle formed by the two sides that it connects.

Let's call the length of a side of the square s. Then, the distance AM can be found using the Pythagorean theorem:

AM = sqrt((5 - 2)^2 + (1 - 1)^2) = sqrt(3^2 + 0^2) = sqrt(9) = 3

So, the length of a side of the square is 2 * AM = 2 * 3 = 6.

Next, we can use the length of a side and the coordinates of A to find the coordinates of B. Since AB is a side of the square and is 6 units long, we can find B by moving 6 units to the right of A:

B = (2 + 6, 1) = (8, 1)

We can also find the coordinates of C by moving 6 units up and 6 units to the left of A:

C = (2 - 6, 1 + 6) = (-4, 7)

Finally, we can find the coordinates of D by moving 6 units down and 6 units to the right of A:

D = (2 + 6, 1 - 6) = (8, -5)

So, the coordinates of the other vertices of the square are B = (8, 1), C = (-4, 7), and D = (8, -5).