Question

2 KCIO3 = 2 KCI + 3 O2

If 12.0 grams of potassium chlorate decompose, how many grams of potassium chloride will be
produced? Round your answer to the nearest hundredths.

Answer 1

7.30g Potassium Chloride (KCl)

Step-by-step explanation:

You are given 12.0 grams of KClO3, so start with that!

12g KClO3
`(12g KClO3)/( ) (1 mol KClO3)/(122.55g) (2 mol KCl)/(2 mol KClO3) (74.55g KCl)/(1 mol KCl) = 7.299877601`≈7.30