Question

Find the surface area (in square feet) of a right circular cylinder of height 4 feet whose base has radius 3 feet. Round the answer to the nearest tenth of a square foot.

Answer 1

After rounding the nearest tenth of a square foot, the surface area of the circular cylinder is 131.88 feet^2.

Explanation:

To find surface area of a right circular cylinder we can use the formula,

A = 2πrh + 2πr^2

Here A is surface area,

π is mathematical constant ,

r is radius, and h is the height of the cylinder.

We have

r = 3 ft

h = 4 ft,

Now we put the values to find the surface area,

A = 2π × 3 × 4 + 2π ×3^2

A = 24π + 18π

A = 42π

A= 42×3.14 (we know π = 3.14 )

A = 131.88

After rounding the nearest tenth of a square foot, the surface area of the circular cylinder is 131.88 feet^2.