Question

A bouncy ball is dropped such that the height of its first bounce is 5 feet and each

successive bounce is 68% of the previous bounce's height. What would be the height
of the 9th bounce of the ball? Round to the nearest tenth (if necessary).

Answer 1

I know, I answer quick. What do you expect I'm Johnny Sins to help you with your homework. :)

Anyways,

The height of the nth bounce can be calculated using the formula:

h_n = h_1 * 0.68^(n-1)

Where h_1 is the height of the first bounce, h_n is the height of the nth bounce, and 0.68 is the percentage of the height lost with each successive bounce.

Substituting the given values, we have:

h_9 = 5 * 0.68^(9-1)

h_9 = 5 * 0.68^8

h_9 = 5 * 0.265

h_9 = 1.325

So the height of the 9th bounce would be approximately 1.3 feet, rounded to the nearest tenth.

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