To find the elongation of the spring, we can use Hooke's Law, which states that the force exerted by a spring is proportional to its elongation. The formula for Hooke's law is:
F = -kx
where F is the force, k is the spring constant, and x is the elongation.
In this case, the force is equal to the weight of the object (10 kg), which can be calculated as:
F = m * g
where m is the mass of the object (10 kg) and g is the acceleration due to gravity (9.8 m/s^2).
So, the force can be calculated as:
F = 10 kg * 9.8 m/s^2 = 98 N
Using Hooke's law, we can find the elongation of the spring:
F = -kx
98 N = -250 N/m * x
x = 98 N / 250 N/m = 0.392 m
So, the elongation of the spring is 0.392 m.
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