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33 votes
Its the special right triangles, and I need help solving them.

Its the special right triangles, and I need help solving them.-example-1
User Jen Bohold
by
2.8k points

1 Answer

26 votes
26 votes
Answer:

ED = 8

DF = 8√2

Explanations:

7) The given triangle is a right - angled triangle

The side ED is the opposite because iut is directly facing the angle 45°

The side DF is the hypotenuse because it is the longest side on the triangle

The side EF is the adjacent

From the given triangle:

EF = 8

θ = 45°

We are looking for DF and ED

Note:

Cos θ = Adjacent / Hypotenuse

Cos 45 = 8 / DF


\begin{gathered} \frac{1}{\sqrt[]{2}}=\text{ }(8)/(DF) \\ DF\text{ = 8}\sqrt[]{2} \end{gathered}

tan θ = Opposite / Adjacent

tan 45 = ED / 8

1 = ED / 8

8 = ED

ED = 8

User Dong Chen
by
3.2k points