Question

A leaky faucet is losing water and is filling a 5-gallon bucket every 20 hours. At that

rate, how many gallons of water will the faucet leak in
48 hours?
Show your
work.

Answer 1

Explanation:

We can start by finding the amount of water the leaky faucet loses in one hour:

5 gallons / 20 hours = 0.25 gallons per hour

This means that the leaky faucet loses 0.25 gallons of water every hour.

To find how many gallons of water the faucet will leak in 48 hours, we can multiply the rate of leakage per hour by the number of hours:

0.25 gallons/hour x 48 hours = 12 gallons

Therefore, the leaky faucet will lose 12 gallons of water in 48 hours.

Answer 2

To find the number of gallons of water leaked by the faucet in 48 hours, we need to multiply the number of gallons leaked per hour by the number of hours:

gallons leaked per hour = 5 gallons / 20 hours = 5/20 gallons/hour

gallons leaked in 48 hours = (5/20 gallons/hour) * 48 hours = (5/20) * 48 gallons
gallons leaked in 48 hours = 12 gallons

So, the faucet will leak a total of 12 gallons in 48 hours.