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F(x) = -x² + 5 and g(x) = -2x+2, find all values of x for which f(x) = g(x).

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Equate Both equatios and find x

  • f(x)=g(x)
  • -x²+5=-2x+2
  • x²-5=2x-2
  • x²-2x-3=0
  • (x+1)(x-3)=0

The points are -1,3

User Tatsuya
by
8.1k points
4 votes

Answer:

The values of x for which f(x) = g(x) are:

  • x = -1
  • x = 3

Explanation:

To find all the values of x for which f(x) = g(x), equate the given functions:


\implies f(x)=g(x)


\implies -x^2+5=-2x+2

Rearrange the equation so that it is in the quadratic form ax²+bx+c=0:


\implies -x^2+5+2x-2=0


\implies -x^2+2x+3=0

Divide both sides by -1:


\implies x^2-2x-3=0

Factor the quadratic equation:


\implies x^2-3x+x-3=0


\implies x(x-3)+1(x-3)=0


\implies (x+1)(x-3)=0

To solve for x, apply the zero-product property:


(x+1)=0 \implies x=-1


(x-3)=0 \implies x=3

Therefore, the values of x for which f(x) = g(x) are:

  • x = -1
  • x = 3

We can check the solutions by substituting each found value of x into the functions.


f(-1)=-(-1)^2+5=4


g(-1)=-2(-1)+2=4


f(3)=-(3)^2+5=-4


g(3)=-2(3)+2=-4

As f(-1) = g(-1) and f(3) = g(3), this proves that the values of x for which f(x) = g(x) are x = -1 or x = 3.

User HowDoIDoComputer
by
8.5k points

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