Question

How many moles of Phosphorous are

needed to completely react with 3.25
moles of Calcium?
2 P + 3 Ca --> Ca3P2

A) 4.88 moles P
B) 2.17 moles P
C) 3.25 moles P

Answer 1

Answer: B) 2.17 moles P

Step-by-step explanation:

To determine the number of moles of Phosphorous needed to completely react with 3.25 moles of Calcium, we need to look at the balanced chemical equation for the reaction:

2 P + 3 Ca → Ca3P2

From the equation, we see that two moles of Phosphorous are needed for every three moles of Calcium. To calculate the number of moles of Phosphorous needed for 3.25 moles of Calcium, we divide the number of moles of Calcium by 3 and multiply by 2:

3.25 moles Ca / 3 moles Ca/2 moles P * 2 moles P/1 mole Ca = 2.17 moles P

So, 2.17 moles of Phosphorous are needed to completely react with 3.25 moles of Calcium.