Question

5. In humans, normal skin color (A) is dominant over albino (a) and diabete

has been found to be inherited (in some cases) through a recessive
allele. A diabetic albino man marries an normal woman whose mother
was an albino and whose father was diabetic. What are the genotypes
of the man and woman? What percentage of their children would be
expected to be both non-diabetic and have normal color?

Answer 1

The genotype of the man would be Aa (one dominant and one recessive allele for albinism) and the genotype of the woman would be Aa (one dominant and one recessive allele for albinism). The percentage of their children that would be expected to be both non-diabetic and have normal color would be 75%, as this would be the result of two Aa genotypes.