Question

Evaluate the limit limx approches 0 x square+ x over x

Answer 1

Explanation:

If we use direct substitution, we will get

`(0)/(0)`

Which is intermediate from so we must use.algebraic manipulation

Let's divide everything by x

We would get

`(x + 1)/(1)`

So the limit as x approaches 0 is

`1`

Proof using a graph:

As x gets close and closer to 0, f(x) approaches 1. Limits does not care about discontinuity, only what the function gets closer to.