Question

How do I simplify this into a radical?

Answer 1

Explanation:

To simplify the expression X^(12/7) * Y^(35/7) into its simplest form, we need to find the greatest common divisor (GCD) of the exponents 12/7 and 35/7 and divide both exponents by the GCD. Here's the step-by-step process:

Find the GCD of 12/7 and 35/7. To do this, we'll use the Euclidean algorithm method:

a. Divide the larger number, 35, by the smaller number, 12, and get the remainder: 35 ÷ 12 = 2 with a remainder of 11.

b. Divide the smaller number, 12, by the remainder, 11, and get the quotient and remainder: 12 ÷ 11 = 1 with a remainder of 1.

c. The last non-zero remainder, 1, is the GCD of 12/7 and 35/7.

Divide both exponents by the GCD, 1:

a. X^(12/7) becomes X^(12/7 ÷ 1) = X^12.

b. Y^(35/7) becomes Y^(35/7 ÷ 1) = Y^35.

Replace the original exponents in the expression with the simplified exponents: X^12 * Y^35.

So, the expression X^(12/7) * Y^(35/7) is simplified as X^12 * Y^35, which is written as a single radical in its simplest form.

Answer 2

`~\hspace{7em}\textit{rational exponents} \\\\ a^{( n)/( m)} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-( n)/( m)} \implies \cfrac{1}{a^{( n)/( m)}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] ~\dotfill\\\\ x^{(12)/(7)}y^{(35)/(7)}\implies \left( x^(12) y^(35) \right)^{(1)/(7)}\implies \sqrt[7]{x^(12) y^(35)}\implies \sqrt[7]{x^(7+5) (y^5)^7} \\\\\\ \sqrt[7]{x^7 x^5 (y^5)^7}\implies {\Large \begin{array}{llll} x y^5\sqrt[7]{x^5} \end{array}}`