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Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar. Glucose solutions are used to treat patients with low blood sugar.

Suppose you prepare a glucose solution using the described procedure.
Step 1: Dissolve 227.9 g of glucose in enough water to make 500.0 mL of solution.
Step 2: Transfer 16.8 mL of the solution to a new flask and add enough water to make 250.0 mL of dilute solution.
What is the concentration (in M) of the glucose solution at the end of the procedure?

User Legatro
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2 Answers

7 votes

Answer:

0.0456 M

Step-by-step explanation:

The concentration of glucose can be determined as follows:

Step 1: Concentration of glucose in the original solution = Mass of glucose / Volume of solution = 227.9 g / (500.0 mL x 10^-3 L/mL) = 0.456 M

Step 2: Concentration of glucose in the dilute solution = Mass of glucose / Volume of dilute solution = 0.456 M x (16.8 mL x 10^-3 L/mL) / (250.0 mL x 10^-3 L/mL) = 0.0456 M

So, the concentration of glucose in the dilute solution is 0.0456 M to 4 significant figures.

ALLEN

5 votes
The concentration (in M) of the glucose solution at the end of the procedure is 0.5M. This can be calculated by dividing the amount of glucose (227.9 g) by the total volume (250 mL) and then dividing this number by the molar mass of glucose (180.16 g/mol). The resulting number is 0.5 M.
User Yu Yang Jian
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