Question

For students majoring in Hospitality Management, it was determined that 5% have visited 1–10 states, 16% have visited 11–20 states, 45% have visited 21–30 states, 19% have visited 31–40 states, and 15% have visited 41–50 states. Suppose a Hospitality Management student is randomly selected. What is the probability that the student has visited 21 or more states?

A . 0.15
B. 0.21
C. 0.45
D. 0.79

Answer 1

D. 0.79

Explanation:

To find the probability that a Hospitality Management student has visited 21 or more states, we need to sum up the probabilities of the categories that represent students who have visited 21 states or more.

The probabilities of the categories are as follows:

Visited 21–30 states: 45% = 0.45

Visited 31–40 states: 19% = 0.19

Visited 41–50 states: 15% = 0.15

So, the total probability of a student having visited 21 or more states is:

0.45 + 0.19 + 0.15 = 0.79.

Therefore, the probability that a Hospitality Management student has visited 21 or more states is 0.79 or 79%.