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In how many ways can the digits number 8,622,222 be arranged?

User Msinfo
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2 Answers

17 votes
17 votes

Answer:105

Explanation:

User Samuel Hsieh
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23 votes
23 votes

The given number is : 8,622,222

Since, there are 7 digits total, Normally the arrangenments of 7 distinct elements are 7!

But in the given number, there are five 2 digit number and one 8 digit number as well as one 6 digit number

From the properties of Permutation: The arrangement of p and q similar elements out of total n elements the arrangements are : n!/p! q!


\begin{gathered} \text{ Permutation of 8622222=}(7!)/(5!) \\ \text{ Permutation of 8622222=}(7*6*5!)/(5!) \\ \text{ Permutation of 8622222=}(7*6*1)/(1) \\ \text{ Permutation of 8622222=}42 \end{gathered}

Arrangements of 8,622,222 digits are 42

Answer : 42 arrangements

User Randal
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