Question

A group of students must study the oscillatory motion of a pendulum. One end of a light string is attached to the ceiling, and the other end of the string is attached to a mass hanger so that small disks of various masses may be stacked on the hanger, as shown in the figure. Question Students are provided with data in which an experiment was conducted to determine the relationship between the length of the pendulum and the period of oscillation. The data include a pendulum of length 0.5m , for which it took 81 s for the pendulum bob to oscillate 10 times. However, the experiment was conducted at a location that is not near Earth’s surface. The gravitational field strength where the experiment was conducted is most nearly Responses 0.003N/kg

Answer 1

The relationship between the length of a pendulum and its period of oscillation is determined by the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. In this case, the pendulum has a length of 0.5m and took 81 s for 10 oscillations. The gravitational field strength where the experiment was conducted is most nearly 0.003N/kg.

Step-by-step explanation:

The relationship between the length of a pendulum and its period of oscillation is determined by the formula:

T = 2π√(L/g)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. In this case, the pendulum has a length of 0.5m and took 81 s for 10 oscillations. To find the acceleration due to gravity, we can rearrange the formula:

g = (4π²L) / T²

Plugging in the values, we get:

g = (4π² * 0.5m) / (81s/10)² ≈ 0.003N/kg

Therefore, the gravitational field strength where the experiment was conducted is most nearly 0.003N/kg.