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Factorise 1331x³y-11y³x pls i really need it!! thank you :) !!​

User Amza
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1 Answer

2 votes

Answer:

11xy(121x²-y²)

Explanation:

When factorizing, you should always look for what each term has in common.

First, let's look at the coefficients (numbers) in each term: 1331 and 11. Both are divisible by 11, so let's factorize out 11:

1331x³y-11y³x

11(121x³y-y³x)

Looking at the terms in the bracket, we see they both have 'x's in common (121x³y has three x's multiplied in and y³x has one). Let's factorize out this x:

11(121x³y-y³x)

11x(121x²y-y³)

We can also see both terms in the brackets have 'y's in common (121x²y has one y and y³ has three multiplied in). Let's factorize out this y:

11x(121x²y-y³)

11xy(121x²-y²)

Since there is nothing in common left between the terms, we can say the expression is fully factorized!

User RobCroll
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