Question

Propane burns completely in oxygen according to the equation shown.

C3H8 (g)+50₂ (g)=3CO₂ (g)+4H₂O(g)
If 0.1 mole of propane gas is burnt completely. What colume of gaseous product is obtained,
measured at room temperature and pressure?

Answer 1

17.11 L

Step-by-step explanation:

The molar volume of a gas at room temperature (25°C) and pressure (1 atm) is 24.45 L/mol.

0.1 mole of propane reacts with oxygen to form 0.1 x 3 = 0.3 mole of carbon dioxide and 0.1 x 4 = 0.4 mole of water vapor.

The total volume of the gaseous products is 0.3 + 0.4 = 0.7 mole of gas.

Therefore, the volume of gaseous products obtained from the complete combustion of 0.1 mole of propane is 0.7 x 24.45 L/mol = 17.11 L.

Answer 2

17.1L

Step-by-step explanation:

use ideal gas law

PV=nRT

101.325x = 0.7 x 8.314 x 298.15

^
Solve for x

X = 17.12424525 ~~ 17.1L