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Question 1 of 10

How many zeros does the polynomial function, y = (x-2)(x+3)² have?
OA. 1
OB. 3
OC. 2
OD. 4
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User Rmanna
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1 Answer

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Answer:

C. 2

Explanation:

A polynomial function has one or more real numbers as roots or zeros. These roots correspond to the values of x for which the function takes on the value of zero.

In this case, y = (x-2)(x+3)², we can factor the equation to find its zeros. The expression (x-2)(x+3)² can be factored into two terms: (x-2) and (x+3)².

The first term, (x-2), is equal to zero when x = 2, meaning that x = 2 is a root of the function.

The second term, (x+3)², is equal to zero when x = -3, meaning that x = -3 is another root of the function.

So, the function y = (x-2)(x+3)² has two roots, or zeros, at x = 2 and x = -3.

User Ireq
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