Answer:
A) To calculate the pH of a 0.1 mol/L solution of hydrosulfuric acid (H2S), we can first calculate the concentration of hydronium ions (H3O+) produced in solution.
Hydrosulfuric acid dissociates in water according to the following equation:
H2S + H2O → H3O+ + HS-
Since the concentration of hydrosulfuric acid is 0.1 mol/L, the concentration of hydronium ions produced will also be 0.1 mol/L.
Next, we can use the concentration of hydronium ions to calculate the pH of the solution:
pH = -log[H3O+] = -log(0.1) = 1
So, the pH of a 0.1 mol/L solution of hydrosulfuric acid is 1.
B) The concentration of H3O+ present in the solution is 0.1 mol/L.
Step-by-step explanation:
ALLEN