Question

a box is sliding down a ramp attains a velocity of 30 m/s in 3 seconds fron rest. what is the acceleration of the box?

Answer 1

The acceleration of the box is;

`a=10m/s^2`

Step-by-step explanation:

Given;

Final velocity v = 30 m/s

initial velocity u = 0

time taken t = 3 seconds

Acceleration is the change in velocity per unit time.

The acceleration a can be calculated using the formula;

`a=(v-u)/(t)`

substituting the given values we have;

`\begin{gathered} a=(30-0)/(3) \\ a=(30)/(3) \\ a=10m/s^2 \end{gathered}`

The acceleration of the box is;

`a=10m/s^2`