Answer:
D: X: Be3+, Y: 91.6nm.
Step-by-step explanation:
The energy required to photoionize an ion from its excited state depends on the electron configuration and energy levels of the ion. Option D corresponds to the ionization energy for Be3+ from its 3rd excited state, which is known to be 91.6 nm. Options A and C correspond to incorrect ionization energies for Li2+ and cannot be the correct answer.
ALLEN