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The wavelength of energy required to photoionize X from its 3rd excited state is Y nm. Pick the sets of X and Y that are correct.

A: X: Li2+, Y: 163nm
B: X: Be3+, Y: 163nm
C: X: Li2+, Y: 91.6nm
D: X: Be3+, Y: 91.6nm

User Alfredaday
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1 Answer

4 votes

Answer:

D: X: Be3+, Y: 91.6nm.

Step-by-step explanation:

The energy required to photoionize an ion from its excited state depends on the electron configuration and energy levels of the ion. Option D corresponds to the ionization energy for Be3+ from its 3rd excited state, which is known to be 91.6 nm. Options A and C correspond to incorrect ionization energies for Li2+ and cannot be the correct answer.

ALLEN

User Duckboycool
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