Answer: The profit function P(x) can be found by subtracting the cost function C(x) from the revenue function R(x), so:
P(x) = R(x) - C(x) = (-0.5(x-80)^2 + 3,200) - (30x + 200)
The domain of P(x) is the set of all possible values of x for which the profit calculation makes sense. In this case, the company has a maximum capacity of 130 items, so the domain of P(x) is 0 <= x <= 130.
To calculate the profit when producing 50 items and 60 items, we simply plug in these values for x in the profit function:
Profit when producing 50 items = P(50) = (-0.5(50-80)^2 + 3,200) - (30 * 50 + 200) = $2350
Profit when producing 60 items = P(60) = (-0.5(60-80)^2 + 3,200) - (30 * 60 + 200) = $2280
Since the profit is higher for producing 50 items, the company should choose to produce 50 items.
From our model, we can see that as the production increases, the cost also increases linearly with a slope of 30, while the revenue increases parabolically but with a negative slope, meaning that after reaching a certain point, the increase in revenue becomes slower compared to the increase in cost. This is why the profit decreases as the production increases, and therefore the company makes less profit when producing 10 more units.
Explanation: