Well, you didn't tell us what the unit of the 53.14 is. But whatever it is, the force of friction is the same 53.14 of them.
The only way the box can move with constant velocity is if the forces acting on it all add up to zero. So the force of friction to the left, holding it back, must be exactly equal to the force pushng it forward to the right.
Notice that none of this depends on the mass of the box, or WHAT the constant velocity IS. None of that information matters, or makes any difference. It's only included in the question to confuse and distract us.