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(1 point) Find an equation of a line perpendicular to 2 = 10 and passing through the point (3,2). The line is​

User Kowal
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1 Answer

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An equation for a line perpendicular to the line 2 = 10 can be found by finding the slope of that line and then finding the slope of the perpendicular line. The slope of the line 2 = 10 is 0, so the slope of the perpendicular line would be undefined.

The equation of a line with slope m passing through the point (x1, y1) can be written in the form:

y - y1 = m(x - x1)

Since the slope of the line is undefined, the equation of the line would be in the form:

x - x1 = constant

To find the equation of the line that passes through the point (3, 2), we substitute the values into the equation:

x - 3 = constant

So the equation of the line that is perpendicular to the line 2 = 10 and passes through the point (3, 2) is:

x - 3 = constant

or simply:

x = 3.

User Paramvir Singh
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