Question

Solve the right triangle ABC, where C = 90°. Give angles in degrees and minutes. a = 18.7 cm, c = 46.4 cm

b= ? cm (Round to nearest tenth as needed) A= ?°?'(Round to nearest minute as needed) B=?°?'(Round to nearest minute as needed) ​

Answer 1

To solve a right triangle, we can use the Pythagorean theorem, which states that the sum of the squares of the two smaller sides equals the square of the largest side. In this triangle, we have:

a^2 + b^2 = c^2

Plugging in the values we have:

18.7^2 + b^2 = 46.4^2

Solving for b, we have:

b = √(46.4^2 - 18.7^2)

b = √(2159.36 - 349.69)

b = √1809.67

b = 42.6 cm (rounded to the nearest tenth)

Next, we can use the tangent function to find angles A and B:

tan(A) = a/b = 18.7/42.6 = 0.439

A = tan^-1(0.439) = 24° 26' (rounded to the nearest minute)

And, using the Pythagorean theorem:

c^2 = a^2 + b^2 = 18.7^2 + 42.6^2 = 346.69 + 1809.67

B = 90° - A = 90° - 24° 26' = 65° 34' (rounded to the nearest minute)

So the solution is:

a = 18.7 cm

b = 42.6 cm

c = 46.4 cm

A = 24° 26'

B = 65° 34'

C = 90°

Explanation: